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Оцени ответ

1) -v2Cos x Sin x = Cos x
-v2 Cos x Sin x -Cos x = 0
Cos x(-v2 Sin x - 1 ) = 0
Cos x = 0    или   -v2Sin x - 1 = 0
x = ?/2 + ?k, k ?Z -v2Sin x = 1
Sin x = -1/v2
x = (-1)^n arcSin (-1/v2) + n?, n ?Z
x = (-1)^n·(-?/4) + n?, n ?Z
x = (-1)^(n +1) ·?/4 + n?, n ?Z
  2)2Cos x + 1 = 0 или   v-Sin x -1 = 0
2Cos x = -1   v-Sin x = 1|? -Sin x = 1
Cos x = -1/2 -Sin x >0
x = +-arcCos(-1/2) + 2?k , k ?Z Sin x = -1 (нет решения)
x = +- 2?/3 + 2?k , k ?Z
3) Cos 2x = Cos x
2Cos? x - 1 - Cos x = 0
Решаем как квадратное
а) Cosx = 1 б) Cos x = -1/2
x = 2?k, k ?Z x = +- arcCos(-1/2) + 2?n, n?Z
x = +-2?/3 + 2?n, n ?Z
4)vCos 2x = 0 или     tg2x - 1 = 0
2x = ?/2 + ?k , k ?Z tg 2x = 1
x = ?/4 + ?k/2, k ?Z 2x = ?/4 + ?n, n ?Z
x = ?/8 + ?n/2, n ?Z
5)Ctg x - Sin 2x = 0
Cosx/Sin x - 2Sin x Cos x= 0 |·Sin x ?0
Cos x - 2Sin?x Cos x = 0
Cos x(1 - 2Sin?x) = 0
Cos x = 0    или 1 - 2Sin?x = 0
x = ?/2 + ?k , k ?Z Sin?x = 1/2
Sin x = +-v1/2
a)Sin x = 1/v2
x = (-1)^n·?/4 + n?, n ?Z
б) Sin x = -1/v2
x = (-1)^(n +1)·?/4 + m?, m?Z